MCQ
If $\phi (x) = {x^2} + 1$ and $\psi (x) = {3^x}$, then $\phi \{ \psi (x)\} $ and $\psi \{ \phi (x)\} = $
- A${3^{2x + 1}},\;{3^{{x^2} + 1}}$
- B${3^{2x + 1}},\;{3^{{x^2}}} + 1$
- ✓${3^{2x}} + 1,\;{3^{{x^2} + 1}}$
- DNone of these
and $\psi \,\left\{ {\phi \,(x)\,} \right\} = \psi \,({x^2} + 1) = {3^{{x^2} + 1}}$.
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$P = \left\{ {\left( {a,b} \right):{{\sec }^2}\,a - {{\tan }^2}\,b = 1\,} \right\}$. Then $P$ is