MCQ
If points (-4, 4) and (-16, b) lie on the locus $y^2=a x$, then
  • A
    $a= \pm 8, b= \pm 4$
  • $a=-4, b= \pm 8$
  • C
    $a=4, b=-4$
  • D
    $a=-4, b=-16$

Answer

Correct option: B.
$a=-4, b= \pm 8$
(B)
Since, $(-4,4)$ lies on $y^2=a x$
$\begin{array}{l}∴(4)^2=a(-4)
\\\Rightarrow a=-4\end{array}$
Also, $(-16, b)$ lies on $y^2= a x$
∴ $b^2=-4(-16)=64$
$\Rightarrow b= \pm 8$

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