Question
If p(x) = x3 - 3x2 + 2x, find p(0), p(1), p(2). What do you conclude?
✓
Answer
p(x) = x3 - 3x2 + 2x ...(1)
Putting x = 0 in (1), we get
p(0) = 03 - 3 × 02 + 2 × 0 = 0
Thus, x = 0 is a zero of p(x).
Putting x = 1 in (1), we get
p(1) = 13 - 3 × 12 + 2 × 1
= 1 - 3 + 2 = 0
Thus, x = 1 is a zero of p(x).
Putting x = 2 in (1), we get
p(2) = 23 - 3 × 22 + 2 × 2
= 8 - 3 × 4 + 4
= 8 - 12 + 4 = 0
Thus, x = 2 is a zero of p(x).
Putting x = 0 in (1), we get
p(0) = 03 - 3 × 02 + 2 × 0 = 0
Thus, x = 0 is a zero of p(x).
Putting x = 1 in (1), we get
p(1) = 13 - 3 × 12 + 2 × 1
= 1 - 3 + 2 = 0
Thus, x = 1 is a zero of p(x).
Putting x = 2 in (1), we get
p(2) = 23 - 3 × 22 + 2 × 2
= 8 - 3 × 4 + 4
= 8 - 12 + 4 = 0
Thus, x = 2 is a zero of p(x).
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