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Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsPolynomials1 Mark
MCQ
If $\text{p}(\text{x})=\text{x}^2-2\sqrt2\text{x}+1$ then $\text{p}(2\sqrt2)=?$
  • A
    0
  • B
    1
  • C
    $4\sqrt2$
  • D
    -1
✓

Answer

  1. 1
    Solution:
    $\text{p}(\text{x})=\text{x}^2-2\sqrt2\text{x}+1$
    $\text{p}(2\sqrt2)=(2\sqrt2)^2-2\sqrt2(2\sqrt2)+1$
    $=8-8+1$
    $=1$

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