MCQ
If $\sec \theta+\tan \theta=x$, then $\sec \theta=$
- A$\frac{x^2+1}{x}$
- ✓$\frac{x^2+1}{2 x}$
- C$\frac{x^2-1}{2 x}$
- D$\frac{x^2-1}{x}$
✓
Answer
Correct option: B.
$\frac{x^2+1}{2 x}$
B
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