- A$3/8$
- ✓$5/8$
- C$3/4$
- D$5/4$
and $\cos 2\,\theta + \cos 2\,\varphi = 3/2$…..$(ii)$
Square અને adding ,
$\therefore \,({\sin ^2}2\theta + {\cos ^2}2\theta ) + ({\sin ^2}2\phi + {\cos ^2}2\phi )$
$ + 2\,[\sin 2\,\theta \,\sin 2\,\phi + \cos 2\,\theta \,\cos 2\,\phi ] = 1/4 + 9/4$
==> $\cos 2\theta \cos 2\,\phi + \sin 2\theta \sin 2\phi = 1/4$
==> $\cos (2\theta - 2\phi ) = 1/4$
==> ${\cos ^2}(\theta - \phi ) = 5/8$.
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where $A = {\sin ^2}\alpha - \sin \alpha + \frac{1}{4}$
and $B = {\tan ^2}\alpha + \frac{2}{{\sqrt 3 }}\tan \alpha + \frac{1}{3}$ , then the number of value $(s)$ of $\alpha $ in $\left[ { - \frac{{3\pi }}{2},2\pi } \right]$ is - (where $sgnx$ denotes signum function of $x$ )