Question
If $\sin 3A = 1$ and $0 < A < 90^\circ,$ find $\sin A$
✓
Answer
$\sin 3A = 1$
$\sin 3A = \sin90^\circ$
$3A = 90^\circ$
$A = 30^\circ$
$\sin A = \sin30^\circ$
$\sin A =\frac{1}{2}$
$\sin 3A = \sin90^\circ$
$3A = 90^\circ$
$A = 30^\circ$
$\sin A = \sin30^\circ$
$\sin A =\frac{1}{2}$
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