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2. inverse trigonometric function — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths2. inverse trigonometric function1 Mark
MCQ
If $\sin \left( {{{\sin }^{ - 1}}\frac{1}{5} + {{\cos }^{ - 1}}x} \right) = 1$, then $x$ is equal to
  • A
    $1$
  • B
    $0$
  • C
    $\frac{4}{5}$
  • ✓
    $\frac{1}{5}$
✓

Answer

Correct option: D.
$\frac{1}{5}$
d
(d) ${\sin ^{ - 1}}\frac{1}{5} + {\cos ^{ - 1}}x = \frac{\pi }{2}$

$\therefore \,\,{\sin ^{ - 1}}\frac{1}{5} = \frac{\pi }{2} - {\cos ^{ - 1}}x = {\sin ^{ - 1}}x$

$\therefore \,\,\,x = \frac{1}{5}$.

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