Question
If $\sin\theta_1+\sin\theta_2+\sin\theta_3=3,$ then write the valuue of $\cos\theta_1+\cos\theta_2+\cos\theta_3.$
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$\frac{n}{8 !}=\frac{3}{6 !}+\frac{1 !}{4 !}$
A ∪ C