MCQ
If $\sqrt3\tan2\theta-3=0$ then $\theta=?$
- A$15^\circ$
- ✓$30^\circ$
- C$45^\circ$
- D$60^\circ$
✓
Answer
Correct option: B.
$30^\circ$
$\sqrt3\tan2\theta-3=0$
$\Rightarrow\sqrt3\tan2\theta-3$
$\Rightarrow\tan2\theta=\frac{3}{\sqrt3}$
$\Rightarrow\tan2\theta=\sqrt3$
$\Rightarrow\tan2\theta=\tan60^\circ$
$\Rightarrow2\theta=60^\circ$
$\Rightarrow\theta=30^\circ$
$\Rightarrow\sqrt3\tan2\theta-3$
$\Rightarrow\tan2\theta=\frac{3}{\sqrt3}$
$\Rightarrow\tan2\theta=\sqrt3$
$\Rightarrow\tan2\theta=\tan60^\circ$
$\Rightarrow2\theta=60^\circ$
$\Rightarrow\theta=30^\circ$
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