If B - C 2 =x A 2 , then x= - Vidyadip

MCQ

If $\tan \frac{ B - C }{2}=x \cot \frac{A}{2}$, then $x=$

A
$\frac{c-a}{c+a}$
B
$\frac{a-b}{a+b}$
✓
$\frac{b-c}{b+c}$
D
$\frac{ b - c }{ a }$

✓

Answer

Correct option: C.

$\frac{b-c}{b+c}$

(C) By Napier's analogy, we have
$\tan \frac{ B - C }{2}=\frac{ b - c }{ b + c } \cot \frac{ A }{2} \Rightarrow x=\frac{ b - c }{ b + c }$

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