MCQ
If $\text{2x}-\frac32=5\text{x}+\frac34,$ then $x =$
- A$\frac{3}{4}$
- ✓$-\frac{3}{4}$
- C$\frac43$
- D$-\frac43$
As, $2\text{x}-\frac32=\text{5x}+\frac34$
$\Rightarrow2\text{x}-5\text{x}=\frac{3}{4}+\frac{3}{4} ($By transpoing $-\frac32$ to $R.H.S.$ and $5x$ to $L.H.S.)$
$\Rightarrow-3\text{x}=\frac{6}{4}+\frac34$
$\Rightarrow-3\text{x}=\frac{6+3}{4}$
$\Rightarrow\text{x}=\frac{9}{4\times(-3)} ($By transposing $-3$ to $R.H.S.)$
$\Rightarrow\text{x}=\frac{3}{4\times(-1)}$
$\Rightarrow\text{x}=\frac{3}{-4}$
$\therefore\text{x}=-\frac34$
Hence, the correct alternative is option $(b).$
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