- A$\theta=\text{n}\pi,\text{n}\in\text{Z}$
- B$\theta=(2\text{n}+1)\frac{\pi}{2},\text{n}\in\text{Z}$
- ✓$\theta=2\text{n}\pi+\frac{\pi}{3},\text{n}\in\text{Z}$
- DNone of these
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($A$) There exists an $\mathrm{h} \in\left[\frac{1}{4}, \frac{2}{3}\right]$ such that the area of the green region above the line $\mathrm{L}_{\mathrm{h}}$ equals the area of the green region below the line $\mathrm{L}_{\mathrm{h}}$
($B$) There exists an $\mathrm{h} \in\left[\frac{1}{4}, \frac{2}{3}\right]$ such that the area of the red region above the line $\mathrm{L}_{\mathrm{h}}$ equals the area of the red region below the line $\mathrm{L}_h$
($C$) There exists an $\mathrm{h} \in\left[\frac{1}{4}, \frac{2}{3}\right]$ such that the area of the green region above the line $\mathrm{L}_{\mathrm{h}}$ equals the area of the red region below the line $L_h$
($D$) There exists an $\mathrm{h} \in\left[\frac{1}{4}, \frac{2}{3}\right]$ such that the area of the red region above the line $\mathrm{L}_{\mathrm{h}}$ equals the area of the green region below the line $\mathrm{L}_{\mathrm{h}}$
$f(x)\left\{ \begin{gathered} = 1\,,\,{\text{if}}\,\,\,x > 0 \hfill \\ = - 1\,,\,{\text{if}}\,\,\,x < 0 \hfill \\ = 0\,,\,{\text{if}}\,\,\,x = 0 \hfill \\ \end{gathered} \right.$ then ${\left. {\frac{{dy}}{{dx}}} \right|_{x = \frac{{5\pi }}{4}}}$ is