MCQ
If the co - efficient of x in $\Big(\text{x}^2+\frac{\lambda}{\text{x}}\Big)^5$is 270, then $ \lambda=$
- A3
- B4
- C5
- DNone of these
Solution:
Now, the co - efficient of x in $\Big(\text{x}^2+\frac{\lambda}{\text{x}}\Big)^5$is ${^6}\text{C}_{3}\cdot(\lambda)^3$or $10(\lambda)^3.$
According to the problem $10(\lambda)^{3}=270,$ or $(\lambda)=3.$
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What is the length of foot of perpendicular drawn from the point P(3, 4, 5) on y-axis.
$\sqrt{41}$
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$\text{None of these.}$