Question
If the displacement is represented by $\text{x}=3\sin\omega\text{t}+4\cos\omega\text{t},$ what is the amplitude?

Answer

Phase difference between $3\sin\omega\text{t}$ and $4\cos\omega\text{t}$ is $\frac{\pi}{2}.$$\therefore$ The amplitude is $\sqrt{3^2+4^2},$ i.e., 5 units.

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