If the potential difference between $B$ and $D$ is zero, the value of $x$ is $\frac{1}{n} \Omega$. The value of $n$ is .......
JEE MAIN 2023, Medium
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$\frac{2}{3}=\frac{\frac{x}{x+1}}{x}$
$\Rightarrow \frac{2}{3}=\frac{1}{x+1}$
$\Rightarrow x=0.5=\frac{1}{2}$
$n=2$
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