MCQ
If the set A has p elements, B has q elements, then the number of elements in A × B is:
- Ap + q
- Bp + q + 1
- Cpq
- Dp2
Solution:
n(A × B) = n(A) × n(B)
n(A × B) = p × q = pq
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If $\text{y}=\frac{\sin(\text{x}+9)}{\cos\text{x}}$ then $\frac{\text{dy}}{\text{dx}}$ at x = 0 is equal to:
$\cos9$
$\sin9$
$0$
$1$