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If the time period of a two meter long simple pendulum is $2\, s$, the acceleration due to gravity at the place where pendulum is executing $S.H.M.$ is
  • A$\pi^{2}\, ms ^{-2}$
  • B$9.8\, ms ^{-2}$
  • C$2 \pi^{2}\, ms ^{-2}$
  • D$16\, m / s ^{2}$
JEE MAIN 2021, Medium
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