MCQ
If the two lines with slope m1 and m2 are perpendicular then their slopes has relation:
- Am1 + m2 = 1
- Bm1 × m2 = 1
- Cm1 × m2 = -1
- Dm1 + m2 = -1
If the two lines with slope m1 and m2 are perpendicular then their slopes has relation:
Solution:
If the two lines are perpendicular then if one line form angle $\alpha$ with positive x-axis then the other line form angle $90^\circ + \alpha$
If $\text{m}_{1} = \tan \alpha$ then m2 will be $\tan (90^\circ + \alpha) = -\cot\alpha = \frac{-1}{\tan\alpha}$
⇒ m1 × m2 = -1.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
If $\text{f}(\text{x})=\frac{\text{x}-4}{2\sqrt{\text{x}}}$ then f'(1) is equal to:
$\frac{5}{4}$
$\frac{4}{5}$
$1$
$0$
All possible outcomes of a random experiment forms the: