MCQ
If two compounds have the same empirical formula but different molecular formula, they must have
- ADifferent percentage composition
- ✓Different molecular weights
- CSame viscosity
- DSame vapour density
✓
Answer
Correct option: B.
Different molecular weights
b
If two compounds have the same empirical formula but different molecular formula, they must have different molecular weights.
If two compounds have the same empirical formula but different molecular formula, they must have different molecular weights.
For example, $CH _2 O$ and $C _6 H _{12} O _6$ have the same empirical formula but different molecular formula, they have different molecular weights.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Combustion of glucose takes place according to the equation, ${C_6}{H_{12}}{O_6} + 6{O_2} \to 6C{O_2} + 6{H_2}O$,$\Delta H = - 72\,kcal$. How much energy will be required for the production of $1.6 \,g$ of glucose......$kcal$. (Molecular mass of glucose $= 180 \,g$)
→If ${K_{sp}}$ for $HgS{O_4}$ is $6.4 \times {10^{ - 5}},$ then solubility of the salt is
→Which of the following structures are aromatic in nature?
Pauli's exclusion principle states that
Which of the following relation represents correct relation between standard electrode potential and equilibrium constant ?
→$I$. $\log \,\,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$
$II$. $K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$
$III$. $\log \,\,K\, = -\,\frac{{nF{E^o}}}{{2.303\,RT}}$
$IV$. $\log \,\,K\, = 0.4342\,\,\frac{{-nF{E^o}}}{{RT}}$
Choose the correct statement $(s)$.
Which statement about the aldol condensation is correct ?
Identify the wrong statement in the following
A reaction $2A \to $ products is found to follow zero oder kinetics, then
→Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
→Assertion $A$ : Order of acidic nature of the following compounds is $A > B > C$.
$image$
Reason $R$ : Fluoro is a stronger electron withdrawing group than Chloro group.
In the light of the above statements, choose the correct answer from the options given below:
The conjugate acid of $NH_2^ - $ is
→