MCQ
If two compounds have the same empirical formula but different molecular formulae they must have
- ADifferent percentage composition
- ✓Different molecular weight
- CSame viscosity
- DSame vapour density
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The enzyme used in the above reaction is
${N_2}\left( g \right) + {O_2}\left( g \right)\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}2NO\left( g \right)$
$C_0 = Ce^{-2.1×10^{-3}\ t}$ for the forward reaction and
$C_0'= C'e^{-4.2×10^{-4}\ t}$ for the backward reaction, hence $K_c$ for the above equilibrium is
