MCQ
If two dice are thrown simultaneously then probability that $1$ comes on first dice is
- A$\frac{1}{{36}}$
- B$\frac{5}{{36}}$
- ✓$\frac{1}{6}$
- DNone of these
Favourable number of ways $= \{ (1,1) (1,2) (1,3) (1,4) (1, 5) (1,6) \}$
$\therefore$ Required probability $= \frac{6}{{36}} = \frac{1}{6}.$
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$[A]$ $\mathrm{P}\left(\mathrm{X}^{\prime} \mid \mathrm{Y}\right)=\frac{1}{2}$ $[B]$ $\mathrm{P}(\mathrm{X} \cap \mathrm{Y})=\frac{1}{5}$ $[C]$ $\mathrm{P}(\mathrm{X} \cup \mathrm{Y})=\frac{2}{5}$ $[D]$ $\mathrm{P}(\mathrm{Y})=\frac{4}{15}$