MCQ
If two different non-axial $d-$ orbitals having $'xz'$ nodal plane form $\pi$ -bond by overlapping each other, then internuclear axis will be
- A$x$
- B$y$
- C$z$
- DThey don't form $\pi$ -bond
✓
Answer
$(d)$ Two different non-axial $d-$ orbitals will lie in planes perpendicular to each other hence, such $d-$ orbital will not form $\pi$ -bond.
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