Gujarat BoardEnglish MediumSTD 9MathsCircles3 Marks
Question
If two non - parallel sides of a trapezium are equal, prove that it is cyclic.
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Answer
Given: Non parallel sides AD and BC of a trapeziumare equal. To prove : ABCD is a cyclic trapezium. Construction: Draw DK $\perp$ AB and CP$\perp$ AB Proof: In it $\Delta ADK$ and $\Delta BCP$ AD=BC DK=CP [Distance between || sides] DKA=CBP [ each 90${}^\circ$ ] By RHS criteria of congruency, $\triangle$DKA $\cong$$\triangle$CPB $\angle A=\angle B $ $\angle ADK=\angle BCP\\ \angle ADK+90{}^\circ =\angle BCP+90{}^\circ $ $\angle ADC=\angle BCD$ $\angle D=\angle C$ ................(ii) $\angle A+\angle B+\angle C+\angle D=360{}^\circ [\angle A= \angle B , \angle C= \angle D]$ $\angle B+\angle B+\angle D+\angle D=360{}^\circ \\ \angle B+\angle D=180{}^\circ $ Hence, ABCD is a cyclic trapezium.
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