MCQ
If $V$ be the accelerating voltage, then the maximum frequency of continuous $X -$rays is given by
  • A
    $\frac{\mathrm{eh}}{\mathrm{v}}$
  • B
    $\frac{\mathrm{hv}}{\mathrm{e}}$
  • $\frac{\mathrm{eV}}{\mathrm{h}}$
  • D
    $\frac{\mathrm{h}}{\mathrm{eV}}$

Answer

Correct option: C.
$\frac{\mathrm{eV}}{\mathrm{h}}$
$\frac{\mathrm{eV}}{\mathrm{h}}$

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