- ✓$ - 2, - 4, - \frac{2}{3}$
- B$ 2, - 4, \frac{2}{3}$
- C$ - 2, 4, \frac{2}{3}$
- D$ 2, 4, - \frac{2}{3}$
$\Rightarrow \alpha=-2 ; \beta=-4: \gamma=-\frac{2}{3}$
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$f(x)=\frac{\cos ^{-1}\left(\frac{x^{2}-5 x+6}{x^{2}-9}\right)}{\log _{e}\left(x^{2}-3 x+2\right)} \text { is }$
$f(x)=\sin x-e^{x} \,\,\,\, \text { if } x \leq 0$
$\quad\quad\quad a+[-x] \,\,\,\, \text { if } 0\,<\,x\,<\,1$
$\quad\quad\quad 2 x-b \,\,\,\,\,\,\,\, \text { if } \geq 1$
where $[\mathrm{x}]$ is the greatest integer less than or equal to $\mathrm{x}$. If $\mathrm{f}$ is continuous on $\mathrm{R}$, then $(\mathrm{a}+\mathrm{b})$ is equal to:
$\left[\begin{array}{ccc}1 & \alpha & \alpha^2 \\ \alpha & 1 & \alpha \\ \alpha^2 & \alpha & 1\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{c}1 \\ -1 \\ 1\end{array}\right]$
of linear equations, has infinitely many solutions, then $1+\alpha+\alpha^2=$