Question
If $\vec{\text{a}}=\hat{\text{i}}+\hat{\text{j}}-\hat{\text{k}},\vec{\text{b}}=-\hat{\text{i}}+2\hat{\text{j}}+2\hat{\text{k}}$ and $\vec{\text{c}}=-\hat{\text{i}}+2\hat{\text{j}}-\hat{\text{k}},$ then a unit vector normal to the vectors $\vec{\text{a}}+\vec{\text{b}}$ and $\vec{\text{b}}-\vec{\text{c}}$ is:
  1. $\hat{\text{i}}$
  2. $\hat{\text{j}}$
  3. $\hat{\text{k}}$
  4. $\text{None of these}$

Answer

Get the step-by-step solution for this question inside the Vidyadip app.

Get the answer in the app

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\int {\frac{{{{\sin }^{ - 1}}x - {{\cos }^{ - 1}}x}}{{{{\sin }^{ - 1}}x + {{\cos }^{ - 1}}x}}} dx = $
Let $PQ$ be a diameter of the circle $x ^{2}+ y ^{2}=9 .$ If $\alpha$ and $\beta$ are the lengths of the perpendiculars from $P$ and $Q$ on the straight line, $x+y=2$ respectively, then the maximum value of $\alpha \beta$ is
If ${x^x}{y^y}{z^z} = c$, then ${{\partial z} \over {\partial x}} = $
$\int_{}^{} {\frac{{a\;dx}}{{b + c{e^x}}}} = $
Evaluate: $\int_0^2(x-[x]) d x$
Consider the linear programming problem Max. $Z=4 x+y$
Subject to $x+y \leq 50 ; x+y \geq 100 ; x, y \geq 0$ The max. value of $Z$
Choose the correct answer from the given four options.
Find the value of $\lambda$ such that the vectors $\vec{\text{a}}=2\hat{\text{i}}+\lambda\hat{\text{j}}+\hat{\text{k}}$ and $\vec{\text{a}}=\hat{\text{i}}+2\hat{\text{j}}+3\hat{\text{k}}$ are orthogonal:
  1. $0$
  2. $1$
  3. $\frac{3}{2}$
  4. $-\frac{5}{2}$
Area of the ellipse $\frac{\text{x}^2}{\text{a}^2}+\frac{\text{y}^2}{\text{b}^2}=1$ is:
  1. $4\pi\text{ ab}\text{ sq}.\text{units} $
  2. $2\pi\text{ ab}\text{ sq}.\text{units} $
  3. $\pi\text{ ab}\text{ sq}.\text{units} $
  4. $\frac{\pi\text{ab}}{2}\text{ sq}.\text{units}$
If $a + b + c = 0$, then the solution of the equation $\left| {\,\begin{array}{*{20}{c}}{a - x}&c&b\\c&{b - x}&a\\b&a&{c - x}\end{array}\,} \right| = 0$ is
If $f'\left( x \right) = \sin \,\left( {\log \,x} \right)$ and $y = f\,\left( {\frac{{2x + 3}}{{3 - 2x}}} \right)$, then $\frac{{dy}}{{dx}}$ equals