Question
If $\vec{\text{a}},\vec{\text{b}}$ are two vectors such that $\big|\vec{\text{a}}+\vec{\text{b}}\big|=\big|\vec{\text{b}}\big|,$ then prove that $\vec{\text{a}}+2\vec{\text{b}}$ is perpendicular to $\vec{\text{a}}.$
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$\tan^{-1}\Bigg|\frac{\sqrt{\text{1 + x}}-{\sqrt{\text{1 - x}}}}{\sqrt{\text{1 + x}}+{\sqrt{\text{1 - x}}}}\Bigg|=\frac{\pi}{4}-\frac{1}{2}\cos^{-1}\text{x},-\frac{1}{\sqrt{2}}\leq\text{x}\leq1$.