Question
If ω is the complex cube root of unity, show that
$\left(1+\omega-\omega^2\right)^6=64$
$\left(1+\omega-\omega^2\right)^6=64$
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$p, q, \frac{ q ^2}{ p }, \frac{ q ^3}{ p ^2}, \ldots$
locus of point $P$ such that $P A^2-P B^2=13$.
f(x) =$\frac{x}{\text{tan}3x}$
=$\frac{7}{3}$,for x ≥ 0, at x = 0.