MCQ
If we plot a graph between $\log \,K$ and $\frac{1}{T}$ by Arrhenius equation, the slope is
- A$ - \frac{{{E_a}}}{R}$
- B$ + \frac{{{E_a}}}{R}$
- ✓$ - \frac{{{E_a}}}{{2.303\,R}}$
- D$ + \frac{{{E_a}}}{{2.303\,R}}$
Thus plots of ln $K$ vs $1/T $ will give slope $ = - {E_a}/RT$ or $ - {E_a}/2.303R$.
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${H_2}O + {H_2}PO^-_4 \rightleftharpoons {H_3}{O^ + } + HPO_4^{ - 2}$
Select out the group of acidic species lying on the right side of the equilibrium
| column $I$ | column $II$ |
| $(A)$ $CO _2( s ) \rightarrow CO _2( g )$ | $(p)$ phase transition |
| $(B)$ $CaCO _3( s ) \rightarrow CaO$ (s) $+ CO _2( g )$ | $(q)$ allotropic change |
| $(C)$ $2 H \bullet \rightarrow H _2( g )$ | $(r)$ $\Delta H$ is positive |
| $(D)$ $P_{\text {(white, solid) }} \rightarrow P_{\text {(red, solid) }}$ | $(s)$ $\Delta S$ is positive |
| $(t)$ $\Delta S$ is negative |