MCQ
If $x = t^2, y = t^3,$ then $\frac{\text{d}^2\text{y}}{\text{dx}^2} =$
- A$\frac{3}{2}$
- ✓$\frac{3}{4\text{t}}$
- C$\frac{3}{2\text{t}}$
- D$\frac{3\text{t}}{2}$
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| $\text{X}$ | $1$ | $2$ | $3$ | $4$ |
| $\text{P}(\text{X})$ | $\frac{1}{10}$ | $\frac{1}{5}$ | $\frac{3}{10}$ | $\frac{2}{5}$ |