MCQ
If x3 + 6x2 + 4x +k is exactly divisible by x + 2 then k =
  • A
    -8
  • B
    -7
  • C
    -6
  • D
    -10

Answer

  1. -8
    Solution:
    -8
    f(x) = x3 + 6x2 + 4x + k
    f(-2) = 0
    $\therefore$ (-2)3 + 6(-2)2 + 4(-2) + k = 0
    $\therefore$ -8 + 6(4) + (-8) + k = 0
    24 - 16 + k = 0
    k + 8 = 0
    k = -8

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