MCQ
If $\text{x}=(7+4\sqrt{3})$ than $\Big(\text{x}+\frac{1}{\text{x}}\Big)=?$
- A49
- B14
- C48
- D$8\sqrt{3}$
✓
Answer
b. 14
Solution :
$\text{x}=(7+4\sqrt{3})$
$\frac{1}{\text{x}}=\frac{1}{7+4\sqrt{3}}=(7-4\sqrt{3})$
$\text{x}+\frac{1}{\text{x}}=(7+4\sqrt{3})+(7-4\sqrt{3})$
$=14$
Solution :
$\text{x}=(7+4\sqrt{3})$
$\frac{1}{\text{x}}=\frac{1}{7+4\sqrt{3}}=(7-4\sqrt{3})$
$\text{x}+\frac{1}{\text{x}}=(7+4\sqrt{3})+(7-4\sqrt{3})$
$=14$
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