MCQ
If $y = {2^{1/{{\log }_x}4}}$, then $ x$ is equal to
- A$\sqrt y $
- B$y$
- ✓${y^2}$
- D${y^4}$
$ \Rightarrow {\log _x}4 = \frac{{\log 2}}{{\log y}} $
$\Rightarrow \frac{{{{\log }_e}4}}{{{{\log }_e}x}} = \frac{{{{\log }_e}2}}{{{{\log }_e}y}} $
$\Rightarrow \frac{{2\log 2}}{{\log x}} = \frac{{\log 2}}{{\log y}}$
==> $2\log y = \log x \Rightarrow x = {y^2}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $Face :$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| $P(F)$ | $0.2$ | $0.22$ | $0.11$ | $0.25$ | $0.05$ | $0.17$ |
The die is tossed and you are told that either face $4$ or face $5$ has turned up. The probability that it is face $4$ is