If y = 3 x^5 + 4 x^4 + 2x + 3, then - Vidyadip

MCQ

If $y = 3{x^5} + 4{x^4} + 2x + 3$, then

A
${y_4} = 0$
B
${y_5} = 0$
✓
${y_6} = 0$
D
None of these

✓

Answer

Correct option: C.

${y_6} = 0$

c
(c) Since highest power of $ x$ is $5$,

therefore ${y_6} = 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. continuity and differentiation→5. continuity and differentiation — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The equation of the line joining the points $(-3,4,11)$ and $(1,-2,7)$ is

The differential equation $2xy\,\, dy = (x^2 + y^2 + 1) dx$ determines

Which of the following functions is inverse of itself

If $y(x)=x^2, x > 0$, then $y^{\prime \prime}(2)-2 y^{\prime}(2)$ is equal to :

$\left| {\,\begin{array}{*{20}{c}}{{{\log }_3}512}&{{{\log }_4}3}\\{{{\log }_3}8}&{{{\log }_4}9}\end{array}\,} \right| \times \left| {\,\begin{array}{*{20}{c}}{{{\log }_2}3}&{{{\log }_8}3}\\{{{\log }_3}4}&{{{\log }_3}4}\end{array}\,} \right|=$

The value of $\cos^{-1}\Big(\cos\Big(\frac{33\pi}{5}\Big)\Big)$ is:

$\frac{3\pi}{5}$
$\frac{-3\pi}{5}$
$\frac{\pi}{10}$
$\frac{-\pi}{10}$

A and B are two students. Their chances of solving a problem correctly are $\frac{1}{3}$ and $\frac{1}{4}$ respectively. If the probability of their making common error is $\frac{1}{20}$ and they obtain the same answer, then the probability of their answer to be correct is.

$\int\frac{\text{xdx}}{(\text{x-1)}(\text{x-2})}$ equals:

$\log\begin{vmatrix}\frac{(\text{x}-1)^2}{\text{x}-2}\end{vmatrix}+\text{c}$
$\log\begin{vmatrix}\frac{(\text{x}-2)^2}{\text{x}-2}\end{vmatrix}+\text{c}$
$\log\begin{vmatrix}\Big(\frac{\text{x}-1}{\text{x}-2}\Big)^2\end{vmatrix}+\text{c}$
$\log|(\text{x}-1)(\text{x}-2)+\text{c}$

Choose the correct answer from the given four options:
The area of the region bounded by the curve x = 2y + 3 and the y lines. y = 1 and y = -1 is:

$4\text{ sq. units}$
$\frac{3}{2}\text{ sq. units}$
$6\text{ sq. units}$
$8\text{ sq. units}$

$\int_{1/e}^e {|\log x|\,dx = } $