MCQ
If $y = {e^{(1 + {{\log }_e}x)}}$, then the value of ${{dy} \over {dx}} = $
  • $e$
  • B
    $1$
  • C
    $0$
  • D
    ${\log _e}x\,\,{e^{{{\log }_e}ex}}$

Answer

Correct option: A.
$e$
a
(a) $y = {e^{1 + {{\log }_e}x}} = {e^1}.{e^{{{\log }_e}x}} = e.x $

$\Rightarrow \frac{{dy}}{{dx}} = e$.

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