If y = x^0, then dy dx = - Vidyadip

MCQ

If $y = \sec {x^0}$, then ${{dy} \over {dx}} = $

A
$\sec x\tan x$
B
$\sec {x^o}\tan {x^o}$
✓
${\pi \over {180}}\sec {x^o}\tan {x^o}$
D
${{180} \over \pi }\sec {x^o}\tan {x^o}$

✓

Answer

Correct option: C.

${\pi \over {180}}\sec {x^o}\tan {x^o}$

c
(c) As ${x^0} = \frac{{\pi x}}{{180}}$ radian.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. continuity and differentiation→5. continuity and differentiation — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If the area bounded by the x - axis, curve y = f (x) and the lines x = 1, x = b is equal to $\sqrt{\text{b}^2+1}-\sqrt{2}$ for all b > 1, then f(x) is:

$\sqrt{\text{x}-1}$
$\sqrt{\text{x}+1}$
$\sqrt{\text{x}^2+1}$
$\frac{\text{x}}{\sqrt{1+\text{x}^2}}$

Correct evaluation of $\int_{}^{} {\frac{x}{{(x - 2)(x - 1)}}\;dx} $ is

(where $p$ is an arbitrary constant)

If $f(x) = 2x + {\cot ^{ - 1}}x + \log (\sqrt {1 + {x^2}} - x)$, then $f(x)$

Lef $f:(0, \pi) \rightarrow R$ be a function given by

$f(x)=\left\{\begin{array}{cc}\left(\frac{8}{7}\right)^{\frac{\tan 8 x}{\tan 7 x}}, & 0 < x < \frac{\pi}{2} \\ a-8, & x=\frac{\pi}{2} \\ (1+\mid \cot x)^{\frac{b}{a}|\tan x|}, & \frac{\pi}{2} < x < \pi\end{array}\right.$

Where $a, b \in Z$. If $f$ is continuous at $x=\frac{\pi}{2}$, then $\mathrm{a}^2+\mathrm{b}^2$ is equal to ..........

$A$ relation $R$ is defined from $\{2, 3, 4, 5\}$ to $\{3, 6, 7, 10\}$ by $xRy \Leftrightarrow x$ is relatively prime to $y$. Then domain of $R$ is

If $A=\left[\begin{array}{lll}3 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 1\end{array}\right]$, then $A$ will be :

The measurement of the area bounded by the co-ordinate axes and the curve $y = {\log _e}x$ is

If $y = {\log _{\sin \,x}}\left( {\tan \,x} \right)$ , then ${\left( {\frac{{dy}}{{dx}}} \right)_{\pi /4}}$ is equal to

If $A$ and $B$ are two events such that $A \subseteq B,$ then $P\,\left( {\frac{B}{A}} \right) = $

If the matrix AB is zero, then:

It is not necessary that either A = 0 or, B = 0
A = 0 or B = 0
A = 0 and B = 0
All the above statements are wrong