MCQ
If $y = x\sin x,$ then
  • ${1 \over y}{{dy} \over {dx}} = {1 \over x} + \cot x$
  • B
    ${{dy} \over {dx}} = {1 \over x} + \cot x$
  • C
    ${1 \over y}{{dy} \over {dx}} = {1 \over x} - \cot x$
  • D
    None of these

Answer

Correct option: A.
${1 \over y}{{dy} \over {dx}} = {1 \over x} + \cot x$
a
(a) $y = x\sin x$==>$\frac{{dy}}{{dx}} = x\cos x + \sin x$ ==>$\frac{1}{y}\frac{{dy}}{{dx}} = \cot x + \frac{1}{x}$.

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