MCQ
If z = 2 - 3i then z2 - 4z + 13 =
- A0
- B1
- C2
- D3
Solutions:
z = 2 - 3i
z2 = 22 - 32 - 12i
= -5 - 12i
$\therefore$ z2 - 4z + 13
= (-5 - 12i) - 4(2 - 3i) + 13
= -5 - 12i - 8 + 12i + 13
= -13 + 13
= 0
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