MCQ
(image) is prepared best by the reaction
- A$(CH_3)_3 C-Br + CH_3OK \to $
- B$(CH_3)_3C-OH$ $\xrightarrow[{170{\,^o}C}]{{{H_2}S{O_4}}}$
- ✓$(CH_3)_3 COK + CH_3-Br \to $
- D$(CH_3)_2 C=CH_2$ $\xrightarrow{{Conc.\,{H_2}S{O_4}}}$
✓
Answer
Correct option: C.
$(CH_3)_3 COK + CH_3-Br \to $
c
$(CH_3)_3COK + CH_3-Br \to (CH_3)_3C-O-CH_3$
$(CH_3)_3COK + CH_3-Br \to (CH_3)_3C-O-CH_3$
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