MCQ
${image}$ The product $"A"$ in the above reaction is
- A
- ✓
- C
- D
✓
Answer
Correct option: B.
b
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$\mathop {Ph - MgBr}\limits^{{\text{[Excess]}}} + $ $\begin{array}{*{20}{c}}
{O\,\,\,\,} \\
{||\,\,\,\,} \\
{Cl - C - C{H_3}}
\end{array}$ $\xrightarrow{{2{H^ \oplus }}}$
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{||\,\,\,\,} \\
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{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
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$\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
Ph-CH=CH-C-C{{H}_{3}}\to Ph-CH=CH-C{{O}_{2}}H \\
\end{matrix}$
→O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
Ph-CH=CH-C-C{{H}_{3}}\to Ph-CH=CH-C{{O}_{2}}H \\
\end{matrix}$
Above conversion can be achieved by