MCQ
${Image}$  The product $"P"$ in the above reaction is
  • A


  • C

  • D

Answer

Correct option: B.

b
$DIBAL$ can not reduce double bond It can reduce cyclic ester.

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A solution containing $0.85\, g$ of $ZnCl_2$ in $125 .0\,g$ of water freezes at $-0.23\,^oC$. The apparent degree of dissociation of the salt is ($K_f$ for water $= 1 .86\, K\,kg\,mol^{-1}$ , atomic mass : ............. $\%$ $Zn = 65 .3$ and $Cl = 35.5$)
Find $(x)$ .
The main product of following reaction will be
Number of hydrogen atoms which can participate in hyperconjugation in $Y$ is
Which of the following does not have optical isomer
Jahn-Teller effect is not observed in high spin complexes of
If the standard electrode potential for a cell is $2\,V$ at $300\,K,$ the equilibrium constant $(K)$ for the reaction

$Zn\,(s)\,\, + \,\,C{u^{2 + }}\,(aq)\, \rightleftharpoons \,Z{n^{2 + \,}}\,(aq)\, + Cu\,(s)$

At $300\,K$ is approximately $(R = 8 \,JK^{-1}\,mol^{-1},\, F = 96000\,C\,mol^{-1})$

Silver mirror is a test for
An aqueous solution of a weak monobasic acid containing $ 0.1\,g$  in $ 21.7\,g$ of water freezes at $272.813\,K$. If the value of ${K_f}$ for water is $1.86\,K/m$, what is the molecular mass of the monobasic acid ........... $g/mole$
The standard reduction potential data at $25^{\circ} C$ is given below.

$E ^0\left( Fe ^{3+} . Fe ^{2+}\right)=+0.77 V $

$E ^0\left( Fe ^{2+} . Fe \right)=-0.44 V $

$E ^{\circ}\left( Cu ^{2+} . Cu \right)=+0.34 V $

$E ^0\left( Cu ^{+} . Cu \right)=+0.52 V $

$E ^{\circ}\left( O _2( g )+4 H ^{+}+4 e ^{-} \rightarrow 2 H _2 O \right)=+1.23 V $

$E ^{\circ}\left( O _2( g )+2 H _2 O +4 e ^{-} \rightarrow 4 OH \right)=+0.40 V $

$E ^0\left( Cr ^{3+} . Cr \right)=-0.74 V $

$E ^{\circ}\left( Cr ^{2+} . Cr \right)=-0.91 V$

Match $E ^{\circ}$ of the rebox pair in List $I$ with the values given in List $II$ and select the correct answer using the code given below the lists:

List $I$ List $II$
$P.$ $\quad E ^{\circ}\left( Fe ^{3+}, Fe \right)$ $1.$ $\quad-0.18 V$
$Q.$ $\quad E ^{\circ}\left(4 H _2 O \rightleftharpoons 4 H ^{+}+4 OH ^{-}\right)$ $2.$ $\quad-0.4 V$
$R.$ $\quad E ^{\circ}\left( Cu ^{2+}+ Cu \rightarrow 2 Cu ^{+}\right)$ $3.$ $\quad-0.04 V$
$S.$ $\quad E ^{\circ}\left( Cr ^{3+}, Cr ^{+2}\right)$ $4.$ $\quad-0.83 V$

Codes: $ \quad P \quad Q \quad R \quad S $