MCQ
Impossible orbital among the following is:
- A3f
- B2p
- C4d
- D2s
Explanation:
If the value of principle quantum number is 3. So the maximum possible value of Azimuthal quantum number is (3 - 1) = 2 which describes the d subshell. But for f subshell, the value of l must be 3. So, 3f orbital is not possible at all.
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| List $-I$ (Molecule / Species) | List $-II$ |
| $(P)$ $NO_2$ (Unpaired electron in) | $(1)$ Vacant $p-$ orbital involved in hybridization |
| $(Q)$ $B_2H_6$ | $(2)$ $sp^2-$ orbital |
| $(R)$ $ClO_3$ (Unpaired electron in) | $(3)$ $sp^3-$orbital |
| $(S)$ $CH_3^+$ | $(4)$ $120^o$ Bond angle |
$2,7-$Dimethyl$\,1 - 2, 6 -$ octadiene $\,\,\overset{{H^+}}{\rightarrow}$ $A$ (Major Product)