In a building there are $15$ bulbs of $45\; \mathrm{W}, 15$ bulbs of $100\; \mathrm{W}, 15$ small fans of $10 \;\mathrm{W}$ and $2$ heaters of $1 \;\mathrm{kW}$. The voltage of electric main is $220\; \mathrm{V}$. The minimum fuse capacity (rated value) of the building will be: .......... $A$
JEE MAIN 2020, Medium
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$220 \mathrm{I}=\mathrm{P}=15 \times 45+15 \times 100+15 \times 10+2 \times 10^{3}$
$I=\frac{4325}{220}=19.66$
$\mathrm{I} \simeq 20 \mathrm{A}$
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