MCQ
In a $G.P., 5^{th}$ term is $27$ and $8^{th}$ term is $729.$ Find its $11^{th}$ term.
  • A
    $729$
  • B
    $2187$
  • C
    $6561$
  • $19683$

Answer

Correct option: D.
$19683$
Given, $a_5 = 27$ and $a_8 = 729.$
$\Rightarrow ar^4 = 27$ and $ar^7 = 729$
On dividing we get, $r^3 = 27$
$\Rightarrow r=3$
$\Rightarrow\text{a}=\frac{23}{(3^4)}=\frac{1}{3}$
$\Rightarrow\text{a}_{11}=\text{a}^{10}$
$=(\frac{1}{3})(3^{10})$
$=39$
$=19683$

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