Question
In a parallelogram it is being given that base $= 14dm$ and height $= 6.5dm$. Find its area in: $cm^2$.
✓
Answer
$\text { Base }=14 \mathrm{dm}=(14 \times 10) \mathrm{cm}=140 \mathrm{~cm}[\text { since } 1 \mathrm{dm}=10 \mathrm{~cm}]$
$ \text { Height }=6.5 \mathrm{dm}=(6.5 \times 10) \mathrm{cm}=65 \mathrm{~cm}$
$ \text { Area of the parallelogram }=\text { Base } \times \text { Height }$
$ =140 \mathrm{~cm} \times 65 \mathrm{~cm}$
$ =9100 \mathrm{~cm}^2$
$ \text { Height }=6.5 \mathrm{dm}=(6.5 \times 10) \mathrm{cm}=65 \mathrm{~cm}$
$ \text { Area of the parallelogram }=\text { Base } \times \text { Height }$
$ =140 \mathrm{~cm} \times 65 \mathrm{~cm}$
$ =9100 \mathrm{~cm}^2$
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