Question
In a parallelogram it is being given that base $= 14\ dm$ and height $= 6.5\ dm$. Find its area in: $m^2$.

Answer

$\text { Base }=14 \mathrm{dm}=(14 \times 10) \mathrm{cm}[\text { since } 1 \mathrm{dm}=10 \mathrm{~cm} \text { and } 100 \mathrm{~cm}=1 \mathrm{~m}]$
$=140 \mathrm{~cm}=1.4 \mathrm{~m}$
$\text { Height }=6.5 \mathrm{dm}=(6.5 \times 10) \mathrm{cm}$
$=65 \mathrm{~cm}=0.65 \mathrm{~m}$
$\therefore \text { Area of the parallelogram }=\text { Base } \times \text { Height }$
$=1.4 \mathrm{~m} \times 0.65 \mathrm{~m}$
$=0.91 \mathrm{~m}^2$

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