In a right triangle ABC, ÐB = 90^ . If AB = 6 cm, BC = 8 cm, find AC

is right - angled at B. Therefore, by applying pythagoras theoram, we obtain A C^2=A B^2+B C^2 A C^2=(6 ~cm)^2+(8 ~cm)^2 A C^2=(36+64) cm^2=100 ~cm^2 AC=(100)cm = (10 10)cm Ac = 10 cm

In a right triangle ABC, ÐB = 90^ . If AB = 6 cm, BC = 8 cm, find…

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Question

In a right triangle $ABC, ÐB = 90^\circ $. If $AB = 6 \ cm, BC = 8 \ cm$, find $AC$

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Answer

$\triangle\text{ABC}$ is right - angled at $B.$
Therefore, by applying pythagoras theoram, we obtain
$ A C^2=A B^2+B C^2 $
$ A C^2=(6 \mathrm{~cm})^2+(8 \mathrm{~cm})^2 $
$ A C^2=(36+64) \mathrm{cm}^2=100 \mathrm{~cm}^2 $
$\text{AC}=(\sqrt{100})\text{cm} = (\sqrt{10\times10})\text{cm}$
$\text{Ac} = 10\text{ cm}$

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Age $($in years$)$	$8$	$9$	$10$	$11$	$12$	$13$	$14$	$15$	$16$	$17$	$18$
Boys	$72\%$	$75\%$	$78\%$	$81\%$	$84\%$	$88\%$	$92\%$	$95\%$	$98\%$	$99\%$	$100\%$
Girls	$77\%$	$81\%$	$84\%$	$88\%$	$91\%$	$95\%$	$98\%$	$99\%$	$99.5\%$	$100\%$	$100\%$