Question
In a $\triangle\text{ABC,}$ it is given that base $= 12\ cm$ and height $= 5\ cm.$ Its area is:
✓
Answer
Area of triangle $=\frac{1}{2}\times\text{Base}\times\text{Height}$
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30 \ \text{cm}^2$
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30 \ \text{cm}^2$
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