MCQ
In a $\triangle\text{ABC,}$ it is given that base $= 12\ cm$ and height $= 5\ cm.$ Its area is:
- A$60\ cm^2$
- ✓$30\ cm^2$
- C$15\sqrt{3}\text{cm}^2$
- D$45\ cm^2$
✓
Answer
Correct option: B.
$30\ cm^2$
Area of triangle $=\frac{1}{2}\times$Base$ \times$Height
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30\text{ cm}^2$
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30\text{ cm}^2$
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